loga+log(a-6)=log(10+3a)

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Solution for loga+log(a-6)=log(10+3a) equation:


Simplifying
loga + log(a + -6) = log(10 + 3a)

Reorder the terms:
aglo + glo(-6 + a) = log(10 + 3a)
aglo + (-6 * glo + a * glo) = log(10 + 3a)

Reorder the terms:
aglo + (aglo + -6glo) = log(10 + 3a)
aglo + (aglo + -6glo) = log(10 + 3a)

Combine like terms: aglo + aglo = 2aglo
2aglo + -6glo = log(10 + 3a)
2aglo + -6glo = (10 * glo + 3a * glo)

Reorder the terms:
2aglo + -6glo = (3aglo + 10glo)
2aglo + -6glo = (3aglo + 10glo)

Solving
2aglo + -6glo = 3aglo + 10glo

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-3aglo' to each side of the equation.
2aglo + -3aglo + -6glo = 3aglo + -3aglo + 10glo

Combine like terms: 2aglo + -3aglo = -1aglo
-1aglo + -6glo = 3aglo + -3aglo + 10glo

Combine like terms: 3aglo + -3aglo = 0
-1aglo + -6glo = 0 + 10glo
-1aglo + -6glo = 10glo

Add '6glo' to each side of the equation.
-1aglo + -6glo + 6glo = 10glo + 6glo

Combine like terms: -6glo + 6glo = 0
-1aglo + 0 = 10glo + 6glo
-1aglo = 10glo + 6glo

Combine like terms: 10glo + 6glo = 16glo
-1aglo = 16glo

Divide each side by '-1glo'.
a = -16

Simplifying
a = -16

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