log(x-6)+log(x-4)-logx=2

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Solution for log(x-6)+log(x-4)-logx=2 equation:


Simplifying
log(x + -6) + log(x + -4) + -1logx = 2

Reorder the terms:
glo(-6 + x) + log(x + -4) + -1logx = 2
(-6 * glo + x * glo) + log(x + -4) + -1logx = 2
(-6glo + glox) + log(x + -4) + -1logx = 2

Reorder the terms:
-6glo + glox + glo(-4 + x) + -1logx = 2
-6glo + glox + (-4 * glo + x * glo) + -1logx = 2
-6glo + glox + (-4glo + glox) + -1logx = 2

Reorder the terms:
-6glo + -4glo + glox + glox + -1glox = 2

Combine like terms: -6glo + -4glo = -10glo
-10glo + glox + glox + -1glox = 2

Combine like terms: glox + glox = 2glox
-10glo + 2glox + -1glox = 2

Combine like terms: 2glox + -1glox = 1glox
-10glo + 1glox = 2

Solving
-10glo + 1glox = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-2 + -10glo + 1glox = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + -10glo + 1glox = 0

The solution to this equation could not be determined.

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