log(x-4)+log(x+2)=1

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Solution for log(x-4)+log(x+2)=1 equation:


Simplifying
log(x + -4) + log(x + 2) = 1

Reorder the terms:
glo(-4 + x) + log(x + 2) = 1
(-4 * glo + x * glo) + log(x + 2) = 1
(-4glo + glox) + log(x + 2) = 1

Reorder the terms:
-4glo + glox + glo(2 + x) = 1
-4glo + glox + (2 * glo + x * glo) = 1
-4glo + glox + (2glo + glox) = 1

Reorder the terms:
-4glo + 2glo + glox + glox = 1

Combine like terms: -4glo + 2glo = -2glo
-2glo + glox + glox = 1

Combine like terms: glox + glox = 2glox
-2glo + 2glox = 1

Solving
-2glo + 2glox = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + -2glo + 2glox = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + -2glo + 2glox = 0

The solution to this equation could not be determined.

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