log(x+2)+log(x-1)=1

Solution for log(x+2)+log(x-1)=1 equation:

Simplifying
log(x + 2) + log(x + -1) = 1

Reorder the terms:
glo(2 + x) + log(x + -1) = 1
(2 * glo + x * glo) + log(x + -1) = 1
(2glo + glox) + log(x + -1) = 1

Reorder the terms:
2glo + glox + glo(-1 + x) = 1
2glo + glox + (-1 * glo + x * glo) = 1
2glo + glox + (-1glo + glox) = 1

Reorder the terms:
2glo + -1glo + glox + glox = 1

Combine like terms: 2glo + -1glo = 1glo
1glo + glox + glox = 1

Combine like terms: glox + glox = 2glox
1glo + 2glox = 1

Solving
1glo + 2glox = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + 1glo + 2glox = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 1glo + 2glox = 0

The solution to this equation could not be determined.