log(x+1)-log(x-1)=log(8)

Solution for log(x+1)-log(x-1)=log(8) equation:

Simplifying
log(x + 1) + -1log(x + -1) = log(8)

Reorder the terms:
glo(1 + x) + -1log(x + -1) = log(8)
(1 * glo + x * glo) + -1log(x + -1) = log(8)
(1glo + glox) + -1log(x + -1) = log(8)

Reorder the terms:
1glo + glox + -1glo(-1 + x) = log(8)
1glo + glox + (-1 * -1glo + x * -1glo) = log(8)
1glo + glox + (1glo + -1glox) = log(8)

Reorder the terms:
1glo + 1glo + glox + -1glox = log(8)

Combine like terms: 1glo + 1glo = 2glo
2glo + glox + -1glox = log(8)

Combine like terms: glox + -1glox = 0
2glo + 0 = log(8)
2glo = log(8)

Reorder the terms for easier multiplication:
2glo = 8glo

Solving
2glo = 8glo

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '-8glo' to each side of the equation.
2glo + -8glo = 8glo + -8glo

Combine like terms: 2glo + -8glo = -6glo
-6glo = 8glo + -8glo

Combine like terms: 8glo + -8glo = 0
-6glo = 0

Divide each side by '-6'.
glo = 0

Simplifying
glo = 0

The solution to this equation could not be determined.