log(x+1)(x-20)=2

Solution for log(x+1)(x-20)=2 equation:

Simplifying
log(x + 1)(x + -20) = 2

Reorder the terms:
glo(1 + x)(x + -20) = 2

Reorder the terms:
glo(1 + x)(-20 + x) = 2

Multiply (1 + x) * (-20 + x)
glo(1(-20 + x) + x(-20 + x)) = 2
glo((-20 * 1 + x * 1) + x(-20 + x)) = 2
glo((-20 + 1x) + x(-20 + x)) = 2
glo(-20 + 1x + (-20 * x + x * x)) = 2
glo(-20 + 1x + (-20x + x2)) = 2

Combine like terms: 1x + -20x = -19x
glo(-20 + -19x + x2) = 2
(-20 * glo + -19x * glo + x2 * glo) = 2
(-20glo + -19glox + glox2) = 2

Solving
-20glo + -19glox + glox2 = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-2 + -20glo + -19glox + glox2 = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + -20glo + -19glox + glox2 = 0

The solution to this equation could not be determined.