log(8x+1)-log(4x-1)=1

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Solution for log(8x+1)-log(4x-1)=1 equation:


Simplifying
log(8x + 1) + -1log(4x + -1) = 1

Reorder the terms:
glo(1 + 8x) + -1log(4x + -1) = 1
(1 * glo + 8x * glo) + -1log(4x + -1) = 1
(1glo + 8glox) + -1log(4x + -1) = 1

Reorder the terms:
1glo + 8glox + -1glo(-1 + 4x) = 1
1glo + 8glox + (-1 * -1glo + 4x * -1glo) = 1
1glo + 8glox + (1glo + -4glox) = 1

Reorder the terms:
1glo + 1glo + 8glox + -4glox = 1

Combine like terms: 1glo + 1glo = 2glo
2glo + 8glox + -4glox = 1

Combine like terms: 8glox + -4glox = 4glox
2glo + 4glox = 1

Solving
2glo + 4glox = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + 2glo + 4glox = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 2glo + 4glox = 0

The solution to this equation could not be determined.

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