log(7)(x)-log(7)(2x-4)=2

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Solution for log(7)(x)-log(7)(2x-4)=2 equation:


Simplifying
log(7)(x) + -1log(7)(2x + -4) = 2

Reorder the terms for easier multiplication:
7glo * x + -1log(7)(2x + -4) = 2

Multiply glo * x
7glox + -1log(7)(2x + -4) = 2

Reorder the terms:
7glox + -1glo * 7(-4 + 2x) = 2

Reorder the terms for easier multiplication:
7glox + -1 * 7glo(-4 + 2x) = 2

Multiply -1 * 7
7glox + -7glo(-4 + 2x) = 2
7glox + (-4 * -7glo + 2x * -7glo) = 2
7glox + (28glo + -14glox) = 2

Reorder the terms:
28glo + 7glox + -14glox = 2

Combine like terms: 7glox + -14glox = -7glox
28glo + -7glox = 2

Solving
28glo + -7glox = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-2 + 28glo + -7glox = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + 28glo + -7glox = 0

The solution to this equation could not be determined.

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