log(5x+4)=1+log(x-2)

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Solution for log(5x+4)=1+log(x-2) equation:


Simplifying
log(5x + 4) = 1 + log(x + -2)

Reorder the terms:
glo(4 + 5x) = 1 + log(x + -2)
(4 * glo + 5x * glo) = 1 + log(x + -2)
(4glo + 5glox) = 1 + log(x + -2)

Reorder the terms:
4glo + 5glox = 1 + glo(-2 + x)
4glo + 5glox = 1 + (-2 * glo + x * glo)
4glo + 5glox = 1 + (-2glo + glox)

Solving
4glo + 5glox = 1 + -2glo + glox

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '2glo' to each side of the equation.
4glo + 2glo + 5glox = 1 + -2glo + 2glo + glox

Combine like terms: 4glo + 2glo = 6glo
6glo + 5glox = 1 + -2glo + 2glo + glox

Combine like terms: -2glo + 2glo = 0
6glo + 5glox = 1 + 0 + glox
6glo + 5glox = 1 + glox

Add '-1glox' to each side of the equation.
6glo + 5glox + -1glox = 1 + glox + -1glox

Combine like terms: 5glox + -1glox = 4glox
6glo + 4glox = 1 + glox + -1glox

Combine like terms: glox + -1glox = 0
6glo + 4glox = 1 + 0
6glo + 4glox = 1

Reorder the terms:
-1 + 6glo + 4glox = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 6glo + 4glox = 0

The solution to this equation could not be determined.

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