log(4x-3)+(x+2)=1

Solution for log(4x-3)+(x+2)=1 equation:

Simplifying
log(4x + -3) + (x + 2) = 1

Reorder the terms:
glo(-3 + 4x) + (x + 2) = 1
(-3 * glo + 4x * glo) + (x + 2) = 1
(-3glo + 4glox) + (x + 2) = 1

Reorder the terms:
-3glo + 4glox + (2 + x) = 1

Remove parenthesis around (2 + x)
-3glo + 4glox + 2 + x = 1

Reorder the terms:
2 + -3glo + 4glox + x = 1

Solving
2 + -3glo + 4glox + x = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -3glo + 4glox + -2 + x = 1 + -2

Reorder the terms:
2 + -2 + -3glo + 4glox + x = 1 + -2

Combine like terms: 2 + -2 = 0
0 + -3glo + 4glox + x = 1 + -2
-3glo + 4glox + x = 1 + -2

Combine like terms: 1 + -2 = -1
-3glo + 4glox + x = -1

Add '-1x' to each side of the equation.
-3glo + 4glox + x + -1x = -1 + -1x

Combine like terms: x + -1x = 0
-3glo + 4glox + 0 = -1 + -1x
-3glo + 4glox = -1 + -1x

Reorder the terms:
1 + -3glo + 4glox + x = -1 + -1x + 1 + x

Reorder the terms:
1 + -3glo + 4glox + x = -1 + 1 + -1x + x

Combine like terms: -1 + 1 = 0
1 + -3glo + 4glox + x = 0 + -1x + x
1 + -3glo + 4glox + x = -1x + x

Combine like terms: -1x + x = 0
1 + -3glo + 4glox + x = 0

The solution to this equation could not be determined.