log(4x-1)+log(x+2)=1

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Solution for log(4x-1)+log(x+2)=1 equation:


Simplifying
log(4x + -1) + log(x + 2) = 1

Reorder the terms:
glo(-1 + 4x) + log(x + 2) = 1
(-1 * glo + 4x * glo) + log(x + 2) = 1
(-1glo + 4glox) + log(x + 2) = 1

Reorder the terms:
-1glo + 4glox + glo(2 + x) = 1
-1glo + 4glox + (2 * glo + x * glo) = 1
-1glo + 4glox + (2glo + glox) = 1

Reorder the terms:
-1glo + 2glo + 4glox + glox = 1

Combine like terms: -1glo + 2glo = 1glo
1glo + 4glox + glox = 1

Combine like terms: 4glox + glox = 5glox
1glo + 5glox = 1

Solving
1glo + 5glox = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + 1glo + 5glox = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 1glo + 5glox = 0

The solution to this equation could not be determined.

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