log(4x-1)(x+4)=1

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Solution for log(4x-1)(x+4)=1 equation:


Simplifying
log(4x + -1)(x + 4) = 1

Reorder the terms:
glo(-1 + 4x)(x + 4) = 1

Reorder the terms:
glo(-1 + 4x)(4 + x) = 1

Multiply (-1 + 4x) * (4 + x)
glo(-1(4 + x) + 4x * (4 + x)) = 1
glo((4 * -1 + x * -1) + 4x * (4 + x)) = 1
glo((-4 + -1x) + 4x * (4 + x)) = 1
glo(-4 + -1x + (4 * 4x + x * 4x)) = 1
glo(-4 + -1x + (16x + 4x2)) = 1

Combine like terms: -1x + 16x = 15x
glo(-4 + 15x + 4x2) = 1
(-4 * glo + 15x * glo + 4x2 * glo) = 1
(-4glo + 15glox + 4glox2) = 1

Solving
-4glo + 15glox + 4glox2 = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + -4glo + 15glox + 4glox2 = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + -4glo + 15glox + 4glox2 = 0

The solution to this equation could not be determined.

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