log(4x+5)+log(x-1)=2

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Solution for log(4x+5)+log(x-1)=2 equation:


Simplifying
log(4x + 5) + log(x + -1) = 2

Reorder the terms:
glo(5 + 4x) + log(x + -1) = 2
(5 * glo + 4x * glo) + log(x + -1) = 2
(5glo + 4glox) + log(x + -1) = 2

Reorder the terms:
5glo + 4glox + glo(-1 + x) = 2
5glo + 4glox + (-1 * glo + x * glo) = 2
5glo + 4glox + (-1glo + glox) = 2

Reorder the terms:
5glo + -1glo + 4glox + glox = 2

Combine like terms: 5glo + -1glo = 4glo
4glo + 4glox + glox = 2

Combine like terms: 4glox + glox = 5glox
4glo + 5glox = 2

Solving
4glo + 5glox = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-2 + 4glo + 5glox = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + 4glo + 5glox = 0

The solution to this equation could not be determined.

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