log(3x-2)+log(x+4)=1

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Solution for log(3x-2)+log(x+4)=1 equation:


Simplifying
log(3x + -2) + log(x + 4) = 1

Reorder the terms:
glo(-2 + 3x) + log(x + 4) = 1
(-2 * glo + 3x * glo) + log(x + 4) = 1
(-2glo + 3glox) + log(x + 4) = 1

Reorder the terms:
-2glo + 3glox + glo(4 + x) = 1
-2glo + 3glox + (4 * glo + x * glo) = 1
-2glo + 3glox + (4glo + glox) = 1

Reorder the terms:
-2glo + 4glo + 3glox + glox = 1

Combine like terms: -2glo + 4glo = 2glo
2glo + 3glox + glox = 1

Combine like terms: 3glox + glox = 4glox
2glo + 4glox = 1

Solving
2glo + 4glox = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + 2glo + 4glox = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 2glo + 4glox = 0

The solution to this equation could not be determined.

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