log(2x-1)log(x+4)=1

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Solution for log(2x-1)log(x+4)=1 equation: 


Simplifying
log(2x + -1) * log(x + 4) = 1

Reorder the terms:
glo(-1 + 2x) * log(x + 4) = 1

Reorder the terms:
glo(-1 + 2x) * glo(4 + x) = 1

Reorder the terms for easier multiplication:
glo * glo(-1 + 2x)(4 + x) = 1

Multiply glo * glo
g2l2o2(-1 + 2x)(4 + x) = 1

Multiply (-1 + 2x) * (4 + x)
g2l2o2(-1(4 + x) + 2x * (4 + x)) = 1
g2l2o2((4 * -1 + x * -1) + 2x * (4 + x)) = 1
g2l2o2((-4 + -1x) + 2x * (4 + x)) = 1
g2l2o2(-4 + -1x + (4 * 2x + x * 2x)) = 1
g2l2o2(-4 + -1x + (8x + 2x2)) = 1

Combine like terms: -1x + 8x = 7x
g2l2o2(-4 + 7x + 2x2) = 1
(-4 * g2l2o2 + 7x * g2l2o2 + 2x2 * g2l2o2) = 1
(-4g2l2o2 + 7g2l2o2x + 2g2l2o2x2) = 1

Solving
-4g2l2o2 + 7g2l2o2x + 2g2l2o2x2 = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + -4g2l2o2 + 7g2l2o2x + 2g2l2o2x2 = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + -4g2l2o2 + 7g2l2o2x + 2g2l2o2x2 = 0

The solution to this equation could not be determined.

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