log(2x-1)(2x-1)=78

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Solution for log(2x-1)(2x-1)=78 equation: 


Simplifying
log(2x + -1)(2x + -1) = 78

Reorder the terms:
glo(-1 + 2x)(2x + -1) = 78

Reorder the terms:
glo(-1 + 2x)(-1 + 2x) = 78

Multiply (-1 + 2x) * (-1 + 2x)
glo(-1(-1 + 2x) + 2x * (-1 + 2x)) = 78
glo((-1 * -1 + 2x * -1) + 2x * (-1 + 2x)) = 78
glo((1 + -2x) + 2x * (-1 + 2x)) = 78
glo(1 + -2x + (-1 * 2x + 2x * 2x)) = 78
glo(1 + -2x + (-2x + 4x2)) = 78

Combine like terms: -2x + -2x = -4x
glo(1 + -4x + 4x2) = 78
(1 * glo + -4x * glo + 4x2 * glo) = 78
(1glo + -4glox + 4glox2) = 78

Solving
1glo + -4glox + 4glox2 = 78

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-78 + 1glo + -4glox + 4glox2 = 78 + -78

Combine like terms: 78 + -78 = 0
-78 + 1glo + -4glox + 4glox2 = 0

The solution to this equation could not be determined.

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