log(2x+1)-log(x-2)=1

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Solution for log(2x+1)-log(x-2)=1 equation:


Simplifying
log(2x + 1) + -1log(x + -2) = 1

Reorder the terms:
glo(1 + 2x) + -1log(x + -2) = 1
(1 * glo + 2x * glo) + -1log(x + -2) = 1
(1glo + 2glox) + -1log(x + -2) = 1

Reorder the terms:
1glo + 2glox + -1glo(-2 + x) = 1
1glo + 2glox + (-2 * -1glo + x * -1glo) = 1
1glo + 2glox + (2glo + -1glox) = 1

Reorder the terms:
1glo + 2glo + 2glox + -1glox = 1

Combine like terms: 1glo + 2glo = 3glo
3glo + 2glox + -1glox = 1

Combine like terms: 2glox + -1glox = 1glox
3glo + 1glox = 1

Solving
3glo + 1glox = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + 3glo + 1glox = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 3glo + 1glox = 0

The solution to this equation could not be determined.

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