log(2x+1)+log(x-2)=log(0.001)

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Solution for log(2x+1)+log(x-2)=log(0.001) equation:


Simplifying
log(2x + 1) + log(x + -2) = log(0.001)

Reorder the terms:
glo(1 + 2x) + log(x + -2) = log(0.001)
(1 * glo + 2x * glo) + log(x + -2) = log(0.001)
(1glo + 2glox) + log(x + -2) = log(0.001)

Reorder the terms:
1glo + 2glox + glo(-2 + x) = log(0.001)
1glo + 2glox + (-2 * glo + x * glo) = log(0.001)
1glo + 2glox + (-2glo + glox) = log(0.001)

Reorder the terms:
1glo + -2glo + 2glox + glox = log(0.001)

Combine like terms: 1glo + -2glo = -1glo
-1glo + 2glox + glox = log(0.001)

Combine like terms: 2glox + glox = 3glox
-1glo + 3glox = log(0.001)

Reorder the terms for easier multiplication:
-1glo + 3glox = 0.001glo

Solving
-1glo + 3glox = 0.001glo

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '-0.001glo' to each side of the equation.
-1glo + -0.001glo + 3glox = 0.001glo + -0.001glo

Combine like terms: -1glo + -0.001glo = -1.001glo
-1.001glo + 3glox = 0.001glo + -0.001glo

Combine like terms: 0.001glo + -0.001glo = 0.000
-1.001glo + 3glox = 0.000

The solution to this equation could not be determined.

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