log(16x)-log(4x)=2

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Solution for log(16x)-log(4x)=2 equation:


Simplifying
log(16x) + -1log(4x) = 2

Remove parenthesis around (16x)
glo * 16x + -1log(4x) = 2

Reorder the terms for easier multiplication:
16glo * x + -1log(4x) = 2

Multiply glo * x
16glox + -1log(4x) = 2

Remove parenthesis around (4x)
16glox + -1glo * 4x = 2

Reorder the terms for easier multiplication:
16glox + -1 * 4glo * x = 2

Multiply -1 * 4
16glox + -4glo * x = 2

Multiply glo * x
16glox + -4glox = 2

Combine like terms: 16glox + -4glox = 12glox
12glox = 2

Solving
12glox = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Divide each side by '12lox'.
g = 0.1666666667l-1o-1x-1

Simplifying
g = 0.1666666667l-1o-1x-1

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