lnx=ln(1+y)+c

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Solution for lnx=ln(1+y)+c equation:


Simplifying
lnx = ln(1 + y) + c
lnx = (1 * ln + y * ln) + c
lnx = (1ln + lny) + c

Reorder the terms:
lnx = c + 1ln + lny

Solving
lnx = c + 1ln + lny

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-1ln' to each side of the equation.
-1ln + lnx = c + 1ln + -1ln + lny

Combine like terms: 1ln + -1ln = 0
-1ln + lnx = c + 0 + lny
-1ln + lnx = c + lny

Add '-1lny' to each side of the equation.
-1ln + lnx + -1lny = c + lny + -1lny

Combine like terms: lny + -1lny = 0
-1ln + lnx + -1lny = c + 0
-1ln + lnx + -1lny = c

Reorder the terms:
-1c + -1ln + lnx + -1lny = c + -1c

Combine like terms: c + -1c = 0
-1c + -1ln + lnx + -1lny = 0

The solution to this equation could not be determined.

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