ln(y+1)=ln(x)+c

Solution for ln(y+1)=ln(x)+c equation:

Simplifying
ln(y + 1) = ln(x) + c

Reorder the terms:
ln(1 + y) = ln(x) + c
(1 * ln + y * ln) = ln(x) + c
(1ln + lny) = ln(x) + c

Multiply ln * x
1ln + lny = lnx + c

Reorder the terms:
1ln + lny = c + lnx

Solving
1ln + lny = c + lnx

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-1lnx' to each side of the equation.
1ln + -1lnx + lny = c + lnx + -1lnx

Combine like terms: lnx + -1lnx = 0
1ln + -1lnx + lny = c + 0
1ln + -1lnx + lny = c

Reorder the terms:
-1c + 1ln + -1lnx + lny = c + -1c

Combine like terms: c + -1c = 0
-1c + 1ln + -1lnx + lny = 0

The solution to this equation could not be determined.