ln(x/3.46)=-0.0568

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Solution for ln(x/3.46)=-0.0568 equation: 


D( x )

x/3.46 <= 0

x/3.46 <= 0

x/3.46 <= 0

0.28901734*x+0 <= 0 // - 0

0.28901734*x <= 0 // : 0.28901734

x <= 0/0.28901734

x <= 0

x in (0:+oo)

ln(x/3.46) = -0.0568 // + 0.0568

ln(x/3.46)+0.0568 = 0

ln(x/3.46)+0.0568 = 0 // - 0.0568

ln(x/3.46) = -0.0568

ln(x/3.46) = ln(e^-0.0568)

x/3.46 = e^-0.0568

x/3.46-e^-0.0568 = 0

0.28901734*x-e^-0.0568 = 0 // + e^-0.0568

0.28901734*x = e^-0.0568 // : 0.28901734

x = (e^-0.0568)/0.28901734

x = 3.46000001*e^-0.0568

x = 3.46000001*e^-0.0568

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