ln(x/0.50)=-0.27

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Solution for ln(x/0.50)=-0.27 equation: 


D( x )

x/0.5 <= 0

x/0.5 <= 0

x/0.5 <= 0

2*x+0 <= 0 // - 0

2*x <= 0 // : 2

x <= 0/2

x <= 0

x in (0:+oo)

ln(x/0.5) = -0.27 // + 0.27

ln(x/0.5)+0.27 = 0

ln(x/0.5)+0.27 = 0 // - 0.27

ln(x/0.5) = -0.27

ln(x/0.5) = ln(e^-0.27)

x/0.5 = e^-0.27

x/0.5-e^-0.27 = 0

2*x-e^-0.27 = 0 // + e^-0.27

2*x = e^-0.27 // : 2

x = (e^-0.27)/2

x = (e^-0.27)/2

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