ln(x+1)-ln(x-1)=ln(2)

Solution for ln(x+1)-ln(x-1)=ln(2) equation:

Simplifying
ln(x + 1) + -1ln(x + -1) = ln(2)

Reorder the terms:
ln(1 + x) + -1ln(x + -1) = ln(2)
(1 * ln + x * ln) + -1ln(x + -1) = ln(2)
(1ln + lnx) + -1ln(x + -1) = ln(2)

Reorder the terms:
1ln + lnx + -1ln(-1 + x) = ln(2)
1ln + lnx + (-1 * -1ln + x * -1ln) = ln(2)
1ln + lnx + (1ln + -1lnx) = ln(2)

Reorder the terms:
1ln + 1ln + lnx + -1lnx = ln(2)

Combine like terms: 1ln + 1ln = 2ln
2ln + lnx + -1lnx = ln(2)

Combine like terms: lnx + -1lnx = 0
2ln + 0 = ln(2)
2ln = ln(2)

Reorder the terms for easier multiplication:
2ln = 2ln

Add '-2ln' to each side of the equation.
2ln + -2ln = 2ln + -2ln

Combine like terms: 2ln + -2ln = 0
0 = 2ln + -2ln

Combine like terms: 2ln + -2ln = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.