ln(x+1)+ln(x-1)=2

Solution for ln(x+1)+ln(x-1)=2 equation:

Simplifying
ln(x + 1) + ln(x + -1) = 2

Reorder the terms:
ln(1 + x) + ln(x + -1) = 2
(1 * ln + x * ln) + ln(x + -1) = 2
(1ln + lnx) + ln(x + -1) = 2

Reorder the terms:
1ln + lnx + ln(-1 + x) = 2
1ln + lnx + (-1 * ln + x * ln) = 2
1ln + lnx + (-1ln + lnx) = 2

Reorder the terms:
1ln + -1ln + lnx + lnx = 2

Combine like terms: 1ln + -1ln = 0
0 + lnx + lnx = 2
lnx + lnx = 2

Combine like terms: lnx + lnx = 2lnx
2lnx = 2

Solving
2lnx = 2

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Divide each side by '2nx'.
l = n-1x-1

Simplifying
l = n-1x-1