ln(x+1)+ln(x-1)=0

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Solution for ln(x+1)+ln(x-1)=0 equation:


Simplifying
ln(x + 1) + ln(x + -1) = 0

Reorder the terms:
ln(1 + x) + ln(x + -1) = 0
(1 * ln + x * ln) + ln(x + -1) = 0
(1ln + lnx) + ln(x + -1) = 0

Reorder the terms:
1ln + lnx + ln(-1 + x) = 0
1ln + lnx + (-1 * ln + x * ln) = 0
1ln + lnx + (-1ln + lnx) = 0

Reorder the terms:
1ln + -1ln + lnx + lnx = 0

Combine like terms: 1ln + -1ln = 0
0 + lnx + lnx = 0
lnx + lnx = 0

Combine like terms: lnx + lnx = 2lnx
2lnx = 0

Solving
2lnx = 0

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Divide each side by '2'.
lnx = 0

Simplifying
lnx = 0

The solution to this equation could not be determined.

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