ln(x)=1+ln(x+1)

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Solution for ln(x)=1+ln(x+1) equation:


Simplifying
ln(x) = 1 + ln(x + 1)

Multiply ln * x
lnx = 1 + ln(x + 1)

Reorder the terms:
lnx = 1 + ln(1 + x)
lnx = 1 + (1 * ln + x * ln)
lnx = 1 + (1ln + lnx)

Add '-1lnx' to each side of the equation.
lnx + -1lnx = 1 + 1ln + lnx + -1lnx

Combine like terms: lnx + -1lnx = 0
0 = 1 + 1ln + lnx + -1lnx

Combine like terms: lnx + -1lnx = 0
0 = 1 + 1ln + 0
0 = 1 + 1ln

Solving
0 = 1 + 1ln

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-1ln' to each side of the equation.
0 + -1ln = 1 + 1ln + -1ln
Remove the zero:
-1ln = 1 + 1ln + -1ln

Combine like terms: 1ln + -1ln = 0
-1ln = 1 + 0
-1ln = 1

Divide each side by '-1n'.
l = -1n-1

Simplifying
l = -1n-1

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