ln(t/6)=1.2

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Solution for ln(t/6)=1.2 equation: 


D( t )

t/6 <= 0

t/6 <= 0

t/6 <= 0

1/6*t+0 <= 0 // - 0

1/6*t <= 0 // : 1/6

t <= 0/1/6

t <= 0

t in (0:+oo)

ln(t/6) = 1.2 // - 1.2

ln(t/6)-1.2 = 0

ln(t/6)-1.2 = 0 // + 1.2

ln(t/6) = 1.2

ln(t/6) = ln(e^1.2)

t/6 = e^1.2

t/6-e^1.2 = 0

1/6*t-e^1.2 = 0 // + e^1.2

1/6*t = e^1.2 // : 1/6

t = (e^1.2)/1/6

t = 6*e^1.2

t = 6*e^1.2

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