ln(7-(1/2)x)=1

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Solution for ln(7-(1/2)x)=1 equation: 


D( x )

7-((1/2)*x) <= 0

7-((1/2)*x) <= 0

7-((1/2)*x) <= 0

(-1/2)*x+7 <= 0

7-1/2*x <= 0 // - 7

-1/2*x <= -7 // : -1/2

x >= -7/(-1/2)

x >= 14

x in (-oo:14)

ln(7-((1/2)*x)) = 1 // - 1

ln(7-((1/2)*x))-1 = 0

ln((-1/2)*x+7)-1 = 0

ln((-1/2)*x+7)-1 = 0 // + 1

ln((-1/2)*x+7) = 1

ln((-1/2)*x+7) = ln(e^1)

(-1/2)*x+7 = e^1

(-1/2)*x-e^1+7 = 0

7-1/2*x-e = 0 // - 7-e

-1/2*x = -(7-e) // : -1/2

x = (-(7-e))/(-1/2)

x = -2*(e-7)

x = -2*(e-7)

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