ln(5x-1)=1/9

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Solution for ln(5x-1)=1/9 equation: 


D( x )

5*x-1 <= 0

5*x-1 <= 0

5*x-1 <= 0

5*x-1 <= 0 // + 1

5*x <= 1 // : 5

x <= 1/5

x in (1/5:+oo)

ln(5*x-1) = 1/9 // - 1/9

ln(5*x-1)-(1/9) = 0

ln(5*x-1)-1/9 = 0

ln(5*x-1)-1/9 = 0 // + 1/9

ln(5*x-1) = 1/9

ln(5*x-1) = ln(e^(1/9))

5*x-1 = e^(1/9)

5*x-e^(1/9)-1 = 0 // + e^(1/9)+1

5*x = e^(1/9)+1 // : 5

x = (e^(1/9)+1)/5

x = (e^(1/9)+1)/5

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