ln(2x-1)+ln(3x+1)=1

Solution for ln(2x-1)+ln(3x+1)=1 equation:

Simplifying
ln(2x + -1) + ln(3x + 1) = 1

Reorder the terms:
ln(-1 + 2x) + ln(3x + 1) = 1
(-1 * ln + 2x * ln) + ln(3x + 1) = 1
(-1ln + 2lnx) + ln(3x + 1) = 1

Reorder the terms:
-1ln + 2lnx + ln(1 + 3x) = 1
-1ln + 2lnx + (1 * ln + 3x * ln) = 1
-1ln + 2lnx + (1ln + 3lnx) = 1

Reorder the terms:
-1ln + 1ln + 2lnx + 3lnx = 1

Combine like terms: -1ln + 1ln = 0
0 + 2lnx + 3lnx = 1
2lnx + 3lnx = 1

Combine like terms: 2lnx + 3lnx = 5lnx
5lnx = 1

Solving
5lnx = 1

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Divide each side by '5nx'.
l = 0.2n-1x-1

Simplifying
l = 0.2n-1x-1