ln(2x-1)+ln(2x+1)=0

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Solution for ln(2x-1)+ln(2x+1)=0 equation:


Simplifying
ln(2x + -1) + ln(2x + 1) = 0

Reorder the terms:
ln(-1 + 2x) + ln(2x + 1) = 0
(-1 * ln + 2x * ln) + ln(2x + 1) = 0
(-1ln + 2lnx) + ln(2x + 1) = 0

Reorder the terms:
-1ln + 2lnx + ln(1 + 2x) = 0
-1ln + 2lnx + (1 * ln + 2x * ln) = 0
-1ln + 2lnx + (1ln + 2lnx) = 0

Reorder the terms:
-1ln + 1ln + 2lnx + 2lnx = 0

Combine like terms: -1ln + 1ln = 0
0 + 2lnx + 2lnx = 0
2lnx + 2lnx = 0

Combine like terms: 2lnx + 2lnx = 4lnx
4lnx = 0

Solving
4lnx = 0

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Divide each side by '4'.
lnx = 0

Simplifying
lnx = 0

The solution to this equation could not be determined.

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