ln(2x+1)=-1/4

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Solution for ln(2x+1)=-1/4 equation:


D( x )

2*x+1 <= 0

2*x+1 <= 0

2*x+1 <= 0

2*x+1 <= 0 // - 1

2*x <= -1 // : 2

x <= -1/2

x in (-1/2:+oo)

ln(2*x+1) = -1/4 // + -1/4

ln(2*x+1)-(-1/4) = 0

ln(2*x+1)+1/4 = 0

ln(2*x+1)+1/4 = 0 // - 1/4

ln(2*x+1) = -1/4

ln(2*x+1) = ln(e^(-1/4))

2*x+1 = e^(-1/4)

2*x-e^(-1/4)+1 = 0 // - 1-e^(-1/4)

2*x = -(1-e^(-1/4)) // : 2

x = (-(1-e^(-1/4)))/2

x = (e^(-1/4)-1)/2

x = (e^(-1/4)-1)/2

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