ln(2x+1)-ln(x+1)=2

Solution for ln(2x+1)-ln(x+1)=2 equation:

Simplifying
ln(2x + 1) + -1ln(x + 1) = 2

Reorder the terms:
ln(1 + 2x) + -1ln(x + 1) = 2
(1 * ln + 2x * ln) + -1ln(x + 1) = 2
(1ln + 2lnx) + -1ln(x + 1) = 2

Reorder the terms:
1ln + 2lnx + -1ln(1 + x) = 2
1ln + 2lnx + (1 * -1ln + x * -1ln) = 2
1ln + 2lnx + (-1ln + -1lnx) = 2

Reorder the terms:
1ln + -1ln + 2lnx + -1lnx = 2

Combine like terms: 1ln + -1ln = 0
0 + 2lnx + -1lnx = 2
2lnx + -1lnx = 2

Combine like terms: 2lnx + -1lnx = 1lnx
1lnx = 2

Solving
1lnx = 2

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Divide each side by '1nx'.
l = 2n-1x-1

Simplifying
l = 2n-1x-1