ln(2*x+1)+ln(x-1)=0

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Solution for ln(2*x+1)+ln(x-1)=0 equation:


Simplifying
ln(2x + 1) + ln(x + -1) = 0

Reorder the terms:
ln(1 + 2x) + ln(x + -1) = 0
(1 * ln + 2x * ln) + ln(x + -1) = 0
(1ln + 2lnx) + ln(x + -1) = 0

Reorder the terms:
1ln + 2lnx + ln(-1 + x) = 0
1ln + 2lnx + (-1 * ln + x * ln) = 0
1ln + 2lnx + (-1ln + lnx) = 0

Reorder the terms:
1ln + -1ln + 2lnx + lnx = 0

Combine like terms: 1ln + -1ln = 0
0 + 2lnx + lnx = 0
2lnx + lnx = 0

Combine like terms: 2lnx + lnx = 3lnx
3lnx = 0

Solving
3lnx = 0

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Divide each side by '3'.
lnx = 0

Simplifying
lnx = 0

The solution to this equation could not be determined.

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