ln(1+3x)=ln(x+1)

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Solution for ln(1+3x)=ln(x+1) equation:


Simplifying
ln(1 + 3x) = ln(x + 1)
(1 * ln + 3x * ln) = ln(x + 1)
(1ln + 3lnx) = ln(x + 1)

Reorder the terms:
1ln + 3lnx = ln(1 + x)
1ln + 3lnx = (1 * ln + x * ln)
1ln + 3lnx = (1ln + lnx)

Add '-1ln' to each side of the equation.
1ln + -1ln + 3lnx = 1ln + -1ln + lnx

Combine like terms: 1ln + -1ln = 0
0 + 3lnx = 1ln + -1ln + lnx
3lnx = 1ln + -1ln + lnx

Combine like terms: 1ln + -1ln = 0
3lnx = 0 + lnx
3lnx = lnx

Solving
3lnx = lnx

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-1lnx' to each side of the equation.
3lnx + -1lnx = lnx + -1lnx

Combine like terms: 3lnx + -1lnx = 2lnx
2lnx = lnx + -1lnx

Combine like terms: lnx + -1lnx = 0
2lnx = 0

Divide each side by '2'.
lnx = 0

Simplifying
lnx = 0

The solution to this equation could not be determined.

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