ln(-x/a)=ln(1-d)/b

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Solution for ln(-x/a)=ln(1-d)/b equation: 


D( x )

1-d <= 0

-x/a <= 0

1-d <= 0

1-d <= 0

1-d <= 0

x należy do R

-x/a <= 0

-x/a <= 0

-x/a = 0

-a^-1*x = 0 // : -a^-1

x = 0

x <= 0

	(-oo:0)	(0:+oo)
x	-	+


x belongs to the empty set

ln(-x/a) = ln(1-d)/b

x belongs to the empty set

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