k=2(11-k)=14

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Solution for k=2(11-k)=14 equation: 



k=2(11-k)=14

We move all terms to the left:

k-(2(11-k))=0

We add all the numbers together, and all the variables

k-(2(-1k+11))=0



We calculate terms in parentheses: -(2(-1k+11)), so:

2(-1k+11)

We multiply parentheses

-2k+22

Back to the equation:

-(-2k+22)



We get rid of parentheses

k+2k-22=0

We add all the numbers together, and all the variables

3k-22=0

We move all terms containing k to the left, all other terms to the right

3k=22

k=22/3

k=7+1/3

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