k2-8k-240=0

Solution for k2-8k-240=0 equation:

k2-8k-240=0

We add all the numbers together, and all the variables

k^2-8k-240=0

a = 1; b = -8; c = -240;
Δ = b2-4ac
Δ = -82-4·1·(-240)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-32}{2*1}=\frac{-24}{2}
=-12
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+32}{2*1}=\frac{40}{2}
=20
$