k/4=4+(2/3)

Solution for k/4=4+(2/3) equation:

k/4=4+(2/3)

We move all terms to the left:

k/4-(4+(2/3))=0

We add all the numbers together, and all the variables

k/4-(4+(+2/3))=0

We calculate fractions


3k^2/()+()/()=0

We add all the numbers together, and all the variables

3k^2/()+1=0

We multiply all the terms by the denominator


3k^2+1*()=0

We add all the numbers together, and all the variables

3k^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$k=\frac{-b}{2a}=\frac{0}{6}=0$