k/4=(k+1)/8

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Solution for k/4=(k+1)/8 equation: 



k/4=(k+1)/8

We move all terms to the left:

k/4-((k+1)/8)=0

We calculate fractions


8k^2/()+(-((k+1)*4)/()=0



We calculate terms in parentheses: +(-((k+1)*4)/(), so:

-((k+1)*4)/(

We multiply all the terms by the denominator


-((k+1)*4)



We calculate terms in parentheses: -((k+1)*4), so:

(k+1)*4

We multiply parentheses

4k+4

Back to the equation:

-(4k+4)



We get rid of parentheses

-4k-4

Back to the equation:

+(-4k-4)



We get rid of parentheses

8k^2/()-4k-4=0

We multiply all the terms by the denominator


8k^2-4k*()-4*()=0

We add all the numbers together, and all the variables

8k^2-4k*()=0

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