k-2(-4k-5)=-10+4k

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Solution for k-2(-4k-5)=-10+4k equation: 



k-2(-4k-5)=-10+4k

We move all terms to the left:

k-2(-4k-5)-(-10+4k)=0

We add all the numbers together, and all the variables

k-2(-4k-5)-(4k-10)=0

We multiply parentheses

k+8k-(4k-10)+10=0

We get rid of parentheses

k+8k-4k+10+10=0

We add all the numbers together, and all the variables

5k+20=0

We move all terms containing k to the left, all other terms to the right

5k=-20

k=-20/5

k=-4

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