k-10/k=6/2

Solution for k-10/k=6/2 equation:

k-10/k=6/2

We move all terms to the left:

k-10/k-(6/2)=0


Domain of the equation: k!=0

k∈R


We add all the numbers together, and all the variables

k-10/k-3=0

We multiply all the terms by the denominator


k*k-3*k-10=0

We add all the numbers together, and all the variables

-3k+k*k-10=0

Wy multiply elements

k^2-3k-10=0

a = 1; b = -3; c = -10;
Δ = b2-4ac
Δ = -32-4·1·(-10)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-7}{2*1}=\frac{-4}{2}
=-2
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+7}{2*1}=\frac{10}{2}
=5
$