k+3/5=2

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Solution for k+3/5=2 equation: 



k+3/5=2

We move all terms to the left:

k+3/5-(2)=0

determiningTheFunctionDomain
k-2+3/5=0

We multiply all the terms by the denominator


k*5+3-2*5=0

We add all the numbers together, and all the variables

k*5-7=0

Wy multiply elements

5k-7=0

We move all terms containing k to the left, all other terms to the right

5k=7

k=7/5

k=1+2/5

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