k+3(2k-5)=4(k-2)-7

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Solution for k+3(2k-5)=4(k-2)-7 equation:


k+3(2k-5)=4(k-2)-7

We simplify the equation to the form, which is simple to understand
k+3(2k-5)=4(k-2)-7

Reorder the terms in parentheses
k+(+6k-15)=4*(k-2)-7

Remove unnecessary parentheses
+k+6k-15=+4+*(+k-2+)-7

Reorder the terms in parentheses
k+6k-15=+(+4k-8)-7

Remove unnecessary parentheses
+k+6k-15=+4k-8-7

We move all terms containing k to the left and all other terms to the right.
+1k+6k-4k=-8-7+15

We simplify left and right side of the equation.
+3k=0

We divide both sides of the equation by 3 to get k.
k=0

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