k+11=3(-3-3k)

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Solution for k+11=3(-3-3k) equation:



k+11=3(-3-3k)
We move all terms to the left:
k+11-(3(-3-3k))=0
We add all the numbers together, and all the variables
k-(3(-3k-3))+11=0
We calculate terms in parentheses: -(3(-3k-3)), so:
3(-3k-3)
We multiply parentheses
-9k-9
Back to the equation:
-(-9k-9)
We get rid of parentheses
k+9k+9+11=0
We add all the numbers together, and all the variables
10k+20=0
We move all terms containing k to the left, all other terms to the right
10k=-20
k=-20/10
k=-2

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