j=4u-(2-u)(2u-2)

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Solution for j=4u-(2-u)(2u-2) equation:


Simplifying
j = 4u + -1(2 + -1u)(2u + -2)

Reorder the terms:
j = 4u + -1(2 + -1u)(-2 + 2u)

Multiply (2 + -1u) * (-2 + 2u)
j = 4u + -1(2(-2 + 2u) + -1u * (-2 + 2u))
j = 4u + -1((-2 * 2 + 2u * 2) + -1u * (-2 + 2u))
j = 4u + -1((-4 + 4u) + -1u * (-2 + 2u))
j = 4u + -1(-4 + 4u + (-2 * -1u + 2u * -1u))
j = 4u + -1(-4 + 4u + (2u + -2u2))

Combine like terms: 4u + 2u = 6u
j = 4u + -1(-4 + 6u + -2u2)
j = 4u + (-4 * -1 + 6u * -1 + -2u2 * -1)
j = 4u + (4 + -6u + 2u2)

Reorder the terms:
j = 4 + 4u + -6u + 2u2

Combine like terms: 4u + -6u = -2u
j = 4 + -2u + 2u2

Solving
j = 4 + -2u + 2u2

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Simplifying
j = 4 + -2u + 2u2

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