j2+2j+1=0

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Solution for j2+2j+1=0 equation: 



j2+2j+1=0

We add all the numbers together, and all the variables

j^2+2j+1=0

a = 1; b = 2; c = +1;
Δ = b2-4ac
Δ = 22-4·1·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$j=\frac{-b}{2a}=\frac{-2}{2}=-1$

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