j-6=1/2*J+3

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Solution for j-6=1/2*J+3 equation: 



j-6=1/2*+3

We move all terms to the left:

j-6-(1/2*+3)=0

We get rid of parentheses

j-6-3-1/2*=0

We multiply all the terms by the denominator


j*2*-1-6*2*-3*2*=0

We add all the numbers together, and all the variables

j*2*=0

Wy multiply elements

2j^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$j=\frac{-b}{2a}=\frac{0}{4}=0$

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