j+(3j-2)=34

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Solution for j+(3j-2)=34 equation: 



j+(3j-2)=34

We move all terms to the left:

j+(3j-2)-(34)=0

We get rid of parentheses

j+3j-2-34=0

We add all the numbers together, and all the variables

4j-36=0

We move all terms containing j to the left, all other terms to the right

4j=36

j=36/4

j=9

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